A qubit can be in two possible states simultaneously when it is under equal superposition — it will either be 1 or 0. It’s like a perfectly unbiased coin in theory (although, it is not. There’s always a noise). Assuming 3 qubits under equal superposition |000>+|111> , there would be 2 possible states ^ 3 qubits = 8 of possible combinations of the state of the 3 qubits after measuring them. It’s the same as flipping 3 independent coins in effect.

But I would argue this is not possible because qubits don’t act like perfectly unbiased coin when they are entangled, hence impossible to derive actual combinations in between. So while what we see after the measurement are 8 possibilities like good old classical probability-it’s going to be one of 000,001,010,100…-each qubit collapses from equal superposition to theoretically infinite state on bloch sphere while performing calculations. Hence I don’t think we could make a claim about possible combinations on infinity…maybe some mathematician did, but I’m no expert in this field haha :)

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r&d blog on architecture, software engineering and inspirations

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